Thermodynamics(hard problem)try to help

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SUMMARY

The discussion focuses on estimating the thermal conductivity of superinsulation used for storing liquid helium in a spherical 200 L container. The superinsulation consists of 7 cm-thick layers of aluminized Mylar sheets. A calculation yielded a thermal conductivity value of 3.1E-6 W/m/K, based on a simplified assumption of uniform temperature within the Mylar thickness. The discussion emphasizes the variability of Mylar's heat conductivity with temperature and suggests further calculations to refine the evaporation rate and temperature profile.

PREREQUISITES
  • Understanding of thermal conductivity and heat transfer principles
  • Familiarity with liquid helium properties, including specific gravity and latent heat of vaporization
  • Basic knowledge of unit conversions and temperature gradients
  • Experience with thermal insulation materials, specifically Mylar
NEXT STEPS
  • Calculate the evaporation rate of liquid helium using real Mylar heat conductivity values
  • Plot the temperature profile within the Mylar insulation thickness
  • Refine calculations to include thermal resistance of surrounding air
  • Research the impact of temperature variations on Mylar's thermal conductivity
USEFUL FOR

Students and professionals in thermodynamics, materials science, and cryogenics, particularly those involved in the storage and handling of liquid helium and thermal insulation technologies.

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Liquid helium is stored in containers fitted with 7 cm-thick "superinsulation" consisting of a large number of layers of very thin aluminized Mylar sheets. The rate of evaporation of liquid in a 200 L container is about 0.7 L per day. Assume that the container is spherical and that the external temperature is 20 C. The specific gravity of liquid helium is 0.125 and the latent heat of vaporization is 21kj/kg. Estimate the thermal conductivity of superinsulation.

This problem is very hard so we need all the help we can get. Even simple ideas in solving the problem will do. Thank you
 
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This problem is extemely simple.
You simply need to use a few definitions, some unit conversions, and the first principle.

I did the calculation and found 3.1E-6 W/m/K .
I did the calculation with the simplified assumption that the temperature gradient is entirely within the mylar thickness. The helium tempreture is assumed to be uniform, as well as the surrounding air temperture.

I checked for the mylar conductivity and found this page: http://www.yutopian.com/Yuan/prop/Mylar.html
You can see that at the liquid helium temperature, this is roughly consistent with the value above.
Unfortunately, the mylar heat conductivity varies by nearly a factor 3 fom 4K to 300K.

Therefore, this exercice is a very simplified version of the reality.

When you are ready with this exercice, you should try to calculate the evaporation rate on the basis of the real mylar heat conductivity that changes quite a lot with temperature. You could also plot the temperature profile within the mylar thickness.

It is also possible to refine the calculation to take into account the thermal resistance of the surrounding air. But I don't know how far you are supposed to go. Let's start with simplified version of this problem.

Tell me if you are supposed to go into more detail.
 
Last edited:
gollum said:
Liquid helium is stored in containers fitted with 7 cm-thick "superinsulation" consisting of a large number of layers of very thin aluminized Mylar sheets. The rate of evaporation of liquid in a 200 L container is about 0.7 L per day. Assume that the container is spherical and that the external temperature is 20 C. The specific gravity of liquid helium is 0.125 and the latent heat of vaporization is 21kj/kg. Estimate the thermal conductivity of superinsulation.

This problem is very hard so we need all the help we can get. Even simple ideas in solving the problem will do. Thank you
How much heat required to evaporate .7 L of He? So how much heat must pass through the insulation in one day? What is that in Joules/sec or Watts? What does that tell you about the thermal conductivity?

AM
 

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