Thermodynamics nitrogen molecules help

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SUMMARY

The discussion focuses on calculating the rate of collisions of nitrogen molecules at 100 degrees Celsius and 2.0 atm pressure using the ideal gas law and collision rate equations. The correct formula for the number of collisions incorporates the average velocity in the x-direction (v_x), which is derived from the root mean square (rms) speed of the nitrogen molecules. The relationship between v_x and v_rms is established as 3*v_x^2 = v_rms^2, leading to the correct calculation of the number of collisions. The final calculation should yield approximately 1.13 x 10^26 collisions per second.

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  • Understanding of the ideal gas law (PV = Nk_bT)
  • Familiarity with root mean square speed (v_rms) and its significance
  • Knowledge of collision rate equations in kinetic theory
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Homework Statement



At 100 celsius the rms speed of nitrogen molecules is 576 m/s. Nitrogen at 100 celsius and a pressure of 2.0 atm is held in a container with a 10cm x 10cm square wall.

Homework Equations



rate of collisions: N_coll/ \Deltat = (N*A*v_x)/(2V) (this is from my textbook)
ideal gas law: N = PV/k_bT (k_b == Boltzmann constant)

The Attempt at a Solution



I took that equation and applied the ideal gas law to replace N,
number of collisions = (P*A*v_x)/(2*k_b*T)
= (2 * 101325 Pa)(.1*.1 m^2)(576m/s) / ( 2 * 1.38 * 10^-23 * (100+273.15) )

after plugging in the numbers I got 1.13 * 10^26, but that's wrong. I'm not sure why.

Thanks!
 
Last edited:
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The equation that you use for the rate of collisions is asking for v_x, not v. v_rms is v. The relationship between the two is 3*v_x^2 = v_rms^2. This is because v_x^2+v_y^2+v_z^2=3*v_x^2=v^2.
 
Ooooh yeeeeeaaah.

THANKS!
 

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