Thermodynamics: property tables HELP

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SUMMARY

The discussion focuses on solving a thermodynamics problem involving R-134a in a piston-cylinder device. Initially, 1 kg of R-134a occupies a volume of 0.14 m³ at -26.4°C, which is identified as a saturated vapor transitioning to a superheated vapor upon heating to 100°C. To determine the final volume, the initial specific volume of 0.14 m³/kg is referenced from thermodynamic tables to find the corresponding pressure. This pressure remains constant, and the specific volume at 100°C is then retrieved from the tables to calculate the new volume.

PREREQUISITES
  • Understanding of thermodynamic properties and phase changes
  • Familiarity with R-134a refrigerant properties
  • Ability to read and interpret thermodynamic property tables
  • Knowledge of the ideal gas law and specific volume calculations
NEXT STEPS
  • Study thermodynamic property tables for R-134a
  • Learn about phase transitions in refrigerants
  • Explore the use of T-V diagrams in thermodynamics
  • Investigate superheated vapor properties and calculations
USEFUL FOR

Students and professionals in mechanical engineering, particularly those focusing on thermodynamics and refrigeration systems, will benefit from this discussion.

MEAHH
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Thermodynamics: property tables HELP!

Homework Statement



1 kg of R-134a fills a 0.14m^3 weighted piston cylinder device at a temperature of -26.4C. The container is now heated until the temp is 100C.
Determine the final volume.


The Attempt at a Solution


So the boiling point is -26.1, so it is a saturated vapor to a superheated vapor?
the specific volume is .14m^3
Pressure is constant? Using a T-V graph?
I don't understand how to go about this problem any help would be great!
 
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At -26.4 C, the initial specific volume is 0.14 m^3/kg. This point needs to be looked up in the thermodynamic tables for the initial pressure. Once the pressure is known, this is also the final pressure. Now, the tables need to be used again to find the specific volume at 100 C and the same pressure. This will be the new volume (since there is 1 kg).
 

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