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Introductory Physics Homework Help
How Does Gas Behavior on a PV Diagram Indicate Changes in Internal Energy?
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[QUOTE="Any Help, post: 5613704, member: 605286"] [h2]Homework Statement [/h2][B]figure: [/B]http://www.chegg.com/homework-help/questions-and-answers/dot-figure-represents-initial-state-gas-isotherm-dot-divides-p-v-diagram-regions-1-2-follo-q5905441 The dot in Figure ([I]b[/I]) represents the initial state of a gas, and the isotherm through the dot divides the [I]p[/I]-[I]V[/I] diagram into regions 1 and 2. For the following processes, determine whether the change Δ[I]E[/I]int in the internal energy of the gas is positive, negative, or zero. [B](a)[/B] the gas moves up along the isotherm[B](b)[/B] the gas moves down along the isotherm[B](c)[/B] the gas moves to anywhere in region 1[B](d)[/B] the gas moves to anywhere in region 21.Δ[I]E[/I]int is positive 2.Δ[I]E[/I]int is negative 3.Δ[I]E[/I]int is zero[h2]Homework Equations[/h2] curve of an isotherm is a hyperbola so as the hyperbola becomes closer to the center (0,0) at its inflection point the temperature decreases deltaE internal= 3/2 nRdelta T means as temperature increases deltaE positive and Vise Versa [h2]The Attempt at a Solution[/h2] when moving on isotherm the delta Einternal will be zero since Einternal depends on the change of temperature the a and b will be zero (a,b =3) but while moving under the curve then we are getting a lesser temperature. the temperature decreases so delta E negative so c is negative (c= 2 similarly for moving above the curve then d is positive (d=1) Is my answer correct? [/QUOTE]
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How Does Gas Behavior on a PV Diagram Indicate Changes in Internal Energy?
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