1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Homework Help: Thermodynamics - Saturated Vapor Quality Question

  1. Mar 4, 2013 #1
    1. The problem statement, all variables and given/known data

    A 4 cubic meter rigid vessel contains 0.04 cubic meters of liquid water and 3.96 cubic meters of water vapor at 101.325 kPa. What is the quality of the saturated vapor?

    2. Relevant equations

    Specific volume of saturated liquid at 100 C and 101.325 kPa: 0.001044 m^3/kg
    Specific volume of saturated vapor at 100 C and 101.325 kPa: 1.67290 m^/kg
    Mass of Vapor = (Volume vapor) / (Specific Volume of sat. vapor)
    Mass of water = (Volume water) / (Specific Volume of sat. liquid)
    x = (Mass of Vapor) / (Total Mass)

    3. The attempt at a solution

    Mass of liquid: 0.04/0.001044 = 38.314 kg
    Mass of vapor: 3.96/1.67290 = 2.367 kg

    x = 2.367/(38.314+2.367) = 0.05818

    Also, for some reason, I thought the quality could be found by specific volumes, which would give me: x = (1.5313-0.001044)/(1.6729) = 0.9147

    Could anyone tell me which method is correct? We have used specific volume to find the quality a few times, which confuses me as to why this would be different.
  2. jcsd
  3. Mar 4, 2013 #2


    User Avatar
    Homework Helper
    Gold Member

    That looks right to me. :approve: (ignoring any trivial rounding differences, if any)
    Forgive me, but I have no idea what you're doing there. You'll have to explain your reasoning.
  4. Mar 4, 2013 #3

    I think I had an error computing the specific volume, and if I correct it with the specific volume of 0.09833 m^3/kg, the I get a quality = (0.09833 - 0.001044) / (1.6729 - 0.001044) = 0.05818

    Sorry for the confusion but I think I found my mistake with the incorrect computation for specific volume.
  5. Mar 5, 2013 #4


    User Avatar
    Homework Helper
    Gold Member

    Okay. But where does the the 0.09833 m3/kg come from? It's the specific volume of what exactly? Again, forgive me, but I'm just not following.
Share this great discussion with others via Reddit, Google+, Twitter, or Facebook

Have something to add?
Draft saved Draft deleted