Thermodynamics-Two Insulated Tank System

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SUMMARY

The discussion focuses on a thermodynamics problem involving two insulated tanks filled with air, one at 1 bar and 300 K, and the other at 10 bar and 300 K. The final temperature after equalizing the mass between the tanks is determined to be approximately 198 K higher in the tank initially at 1 bar. The enthalpy of the air is constant at 300.19 kJ/kg, and the solution involves using the equations PV = mRT and H = U + PV to analyze the energy balance and temperature changes.

PREREQUISITES
  • Understanding of the Ideal Gas Law (PV = mRT)
  • Knowledge of thermodynamic concepts such as enthalpy and internal energy
  • Familiarity with the First Law of Thermodynamics
  • Basic skills in solving thermodynamic equations
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  • Study the First Law of Thermodynamics and its applications in closed systems
  • Learn about energy balance equations in thermodynamic processes
  • Explore the concept of enthalpy in detail, particularly in gas systems
  • Investigate the effects of pressure and temperature changes on gas behavior
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1. Homework Statement

Two large, well-insulated tanks of 2m diameter and 5m in height are filled with air. One tank is initially at 1bar and 300oK and the other is at 10bar at 300oK. Determine the final temperature in both tanks if a valve connecting the two tanks is opened and the mass equalized (mf1=mf2) very quickly then closed again. Assume the enthalpy of the inlet and exit air for each tank is constant at 300.19kJ/kg. (Hint: One tank is ~198oK higher than the other after the valve shuts)

2. Homework Equations

PV=mRT
H=U+PV=U+RT


3. The Attempt at a Solution

I've used PV=mRT for both tanks to find the mass in tank 1 is 18.24kg while the mass in tank 2 is 182.4 kg. This gives a collective mass of 200.64kg. As stated in the problem statement the final mass in both tanks is equal which would then be 100.32 kg. From there I am not quite sure how to incorporate enthalpy into finding the final temperature in each tank?
 
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