Thevenin and norton theorem question

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SUMMARY

The discussion clarifies the application of Thevenin and Norton theorems in circuit analysis. In Thevenin's theorem, the equivalent resistance is calculated in series with the load resistor, while in Norton's theorem, it is calculated in parallel. This distinction is crucial for proving the validity of the theorems, as using the incorrect configuration leads to discrepancies in current and voltage across the load resistor. Understanding these principles is essential for accurate circuit analysis.

PREREQUISITES
  • Understanding of Thevenin's theorem and its application in circuit analysis
  • Familiarity with Norton's theorem and its implications
  • Knowledge of series and parallel resistor configurations
  • Basic principles of electrical circuits and components
NEXT STEPS
  • Study the derivation and proof of Thevenin's theorem
  • Examine the derivation and proof of Norton's theorem
  • Practice circuit analysis using both Thevenin and Norton equivalents
  • Explore advanced applications of Thevenin and Norton theorems in complex circuits
USEFUL FOR

Electrical engineering students, circuit designers, and professionals involved in circuit analysis and design will benefit from this discussion.

rajeshmarndi
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Why in thevenin theorem, we take the equivalent resistance in series to the load resistor, while in norton theorem we take the equivalent resistance parallel to the load resistor.

Thanks.
 
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Because that is what works.
Note: you can take the equivalents without having a load resistor ... think you may benefit from looking up a more general description.
 
yes because that is what it has to be in order to prove the theorems, in order for the theorems to be true. Because if for example you take in norton theorem the "equivalent" resistance in series with the "equivalent" current source and the load resistor, then you just can't prove the theorem. Which means that the supposed "equivalent" resistance and current source (as defined by the theorem) are no longer equivalent i.e the current and the voltage in the load resistor will not be the same with the "equivalent" components in series as they would be if you had the actual circuit.
 
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