Thevinin Question (electrical Crts)

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SUMMARY

The discussion focuses on calculating the Thevenin equivalent circuit for a load, specifically determining the Thevenin voltage and resistance. The Thevenin resistance was established at 4k ohms, and the Thevenin voltage was calculated to be 8 volts. The maximum power transfer occurs when the load resistance equals the Thevenin resistance, yielding a theoretical maximum power of 16mW. However, a discrepancy arose as another participant calculated the maximum power to be 4mW, attributed to an incorrect method of calculating power using the Thevenin voltage instead of the voltage drop across the load resistance.

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seto6
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ok, i want to find a thevinin equvilent so i can replace the circuit at the load with the thevinin equivalent.

so i would end up with a voltage thevinin, thevinin resistance and the load.

now i found the thevinin resistance to be 4k ohm.

now i found the voltage at the load, thus thevinin voltage to be 8 volts.

the max power through the load is when the load is equal to thevinin resistance which is 4k ohm. i calculated the max power transferred to be 16mW, but they got 4mW...where did i go wrong.

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You got everything correct except the power. What exactly did you do to calculate the power?
 
You probably used the Thevenin voltage squared divided by the resistance to calculate the power.You should use the voltage drop across the resistance instead, which should be noted to be half the supply voltage, since the two resistances are equal (Rl = Rth) so the voltage drop across each one should be the same.
Or maybe you just made a mistake with the numbers.
 

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