- #1

TheRedDevil18

- 408

- 1

## Homework Statement

Solve the thevenins equivalent of the circuit

## Homework Equations

## The Attempt at a Solution

I think this is wrong but I got 750 ohms for my Rthevinin and 2.3V for my Vthevinin. I checked using KVL with the load resistor set to 500 ohms and get a current of 0.0037A through the 500 ohm resistor but when I use the thevinins circuit I get a current of 0.0018A

This is how I got Rth,

Short the Voltage source, so the 750 is in parallel with the 1500 which is equivalent to 500 ohm resistor in series with the 1000 ohm to give a 1500 ohm in parallel with the second 1500 ohm to give my Rth of 750 ohms

This is how I got Vth,

Replacing the voltage source I see that the 1500(one connected in the separate branch) and 1000 ohm resistors have no current flowing through them. That leaves just the 1500 and 750 in series with the voltage source. So the voltage across the terminals would equal to the voltage in the 750 ohm resistor which works out to be 2.3V = Vth

Can someone please tell me what I'm doing wrong ?, thanks