Thick spherical shell confirmation of solution

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Homework Help Overview

The problem involves a thick spherical shell characterized by an inner radius a and an outer radius b, containing a uniform charge density ρ and a total charge Q. Participants are tasked with finding the charge density and the electric field in different regions: inside the shell (r < a), within the shell (a < r < b), and outside the shell (b < r). The discussion centers around the calculations and implications of these electric fields.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the calculation of charge density ρ and the electric field in various regions. There is an attempt to derive the expressions for ρ and E, with some questioning the accuracy of the derived equations and the assumptions made regarding the Gaussian surface.

Discussion Status

Some participants have identified errors in the equations presented, particularly regarding the expression for the electric field in the region a < r < b. There is ongoing clarification about the implications of the Gaussian surface and how it relates to the charge enclosed.

Contextual Notes

Participants are navigating through the implications of Gauss' law and the assumptions regarding the charge distribution and symmetry in the problem. There is a focus on ensuring that the derived expressions accurately reflect the physical setup described in the problem statement.

Liquidxlax
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Homework Statement


A spherical shell of inner radius a and outer radius b contains a uniform charge density ρ of total charge Q. (a) Find ρ (b) find the electric field for r< a, a< r< b, b< r sketch it


Homework Equations



E = kQ/r2

V=4πr3

The Attempt at a Solution



ρ π

since it is a thick shell the volume would be V = (4/3)π(b3 - a3)

and ρV = Qenc => ρ=Q/V

so

ρ = 3Q/(4π(b3 - a3))


(b) r<a the electric field will be 0 because the electric field can't close on itself

a< r< b

E=kQenc/r2 = (4πkρ(b3 - a3))/3r3


b<r kQ/r2 because the sphere can be treated as a point charge and the electric field is symmetric on a sphere


Does this look right?
 
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Liquidxlax said:
E= [...] = (4πkρ(b3 - a3))/3r3
There's two errors with the above equation (see the red).
 
collinsmark said:
There's two errors with the above equation (see the red).

okay i see how the r3 is wrong, that was just a transcribing error, but how come the b is wrong? or would it be because we know that r<b so we can assume it to be

(r3-a3) because a is constant and r does not exceed b
 
There you go! :approve: Remember Gauss' law relates to the charge enclosed within the Gaussian surface (the Gaussian surface in this case has radius r). In the case where b > r > a, then any charge between r and b is outside the Gaussian surface, and has no effect (in this spherically symmetrical case).
 

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