SUMMARY
The discussion centers on calculating the smallest nonzero thickness of a soap film that results in constructive interference for light of wavelength 547 nm, with a refractive index (n) of 1.31. The formula used is 2t = (m + 1/2)(wavelength/nfilm). The correct calculation yields a film thickness of 104 nm when m is set to 0. This confirms that the solution provided is accurate and adheres to the principles of optics.
PREREQUISITES
- Understanding of constructive interference in optics
- Familiarity with the refractive index concept
- Knowledge of wavelength and its relation to film thickness
- Ability to manipulate equations involving physical constants
NEXT STEPS
- Study the principles of constructive and destructive interference in thin films
- Learn about the effects of varying refractive indices on light behavior
- Explore the application of the formula 2t = (m + 1/2)(wavelength/nfilm) in different contexts
- Investigate real-world applications of thin film interference in technology
USEFUL FOR
Students studying optics, physics educators, and anyone interested in the practical applications of thin film interference in various scientific fields.