Thickness of material to absorb electron beam

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SUMMARY

The discussion focuses on calculating the thickness of a copper absorber required to fully absorb a 10 MeV electron beam with an intensity of 10^8 (s*cm^2)^-1. The key equation for determining the absorbed dose is D=(1.602*10^-10)*(fluence*E/mass thickness) (Gy). To find the absorber thickness, one must multiply the mass stopping power by the density of copper and divide it by the beam energy. The conditions for complete absorption involve ensuring the thickness meets the criteria for thick foil conditions.

PREREQUISITES
  • Understanding of electron beam physics
  • Knowledge of mass stopping power
  • Familiarity with absorbed dose calculations
  • Basic principles of material interactions with charged particles
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  • Research "mass stopping power for copper" to determine specific values
  • Study "thick foil conditions in particle physics" for absorption criteria
  • Explore "fluence calculations in radiation physics" for accurate dose assessments
  • Learn about "electron beam interactions with matter" for deeper insights
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Students in physics or engineering fields, researchers in radiation safety, and professionals working with electron beam applications will benefit from this discussion.

amrian
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Homework Statement


Beam of electrons (charged particles!) is directed to copper absorber with known energy (E= 10MeV) and intensity (10^8(s*cm^2)^-1) . I need to find the thickness of absorber so that all electrons would be absorbed. Also under what conditions does it happen and what is absorbed dose then?

Homework Equations



D=(1.602*10^-10)* (fluence*E/mass thickness) (Gy)

The Attempt at a Solution



so to get absorber thickness should I mass stopping power multiply by copper density and then divide it from the beam energy?
is it thick foil condition?
 
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if it is, then dose is equal to absorber thickness multiplied by fluence multiplied by energy and divided by mass thickness?
 

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