Thin Lenses: Understanding (3/2)f in Image Formation

  • Thread starter Thread starter libra10489
  • Start date Start date
  • Tags Tags
    Lenses
Click For Summary

Homework Help Overview

The discussion revolves around understanding the relationship between object distance, image distance, and focal length in the context of thin lenses. The original poster is trying to grasp why the image distance is (3/2)f when the object is positioned three times the focal length from the lens.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the lens formula and how to apply it to the given problem. The original poster expresses confusion about the phrasing of the problem and the absence of numerical values. Others suggest using algebra to clarify the relationships between the distances.

Discussion Status

The conversation is progressing with participants guiding the original poster to apply the lens formula. Some participants have provided encouragement and hints to help clarify the problem, but there is no explicit consensus on the understanding of the solution yet.

Contextual Notes

The original poster is working under the constraint of a homework problem, which may limit the information they can use or the methods they can apply. There is a focus on understanding the setup rather than solving for specific values.

libra10489
Messages
4
Reaction score
0

Homework Statement



An object is 3 times further from a a lens than its focal length. Let f rep focal length. How man times the focal length of the lens is the image from the lense? The answer is (3/2)f but I don't understand why. Could someone please explain it to me?
 
Physics news on Phys.org
welcome to pf!

hi libra10489! welcome to pf! :wink:

what equations do you know relating the object distance the image distance and the focal length? :smile:
 
The only one I know is (1/object distance) + (1/image distance) = (1/focal length).
 
that's the one! :wink:

ok, now put the numbers in …

what do you get? :smile:
 
Um...there are no numbers...if there were numbers I'd be able to plug and chug. I guess the confusing part is "An object is 3 times further from a lens than its focal length."
 
use algebra …

call the focal length "f" …

then the object distance is 3f, so the image distance is … ? :smile:
 
Oh..., now I feel stupid... OK I got it. Thanks.
 

Similar threads

Replies
1
Views
2K
  • · Replies 2 ·
Replies
2
Views
1K
Replies
3
Views
3K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 7 ·
Replies
7
Views
3K
  • · Replies 12 ·
Replies
12
Views
5K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 2 ·
Replies
2
Views
4K
  • · Replies 3 ·
Replies
3
Views
2K