(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

http://img183.imageshack.us/img183/7473/56823155cm1.th.jpg [Broken]

Lets all the top positive 6 microC charge, 'A', and the bottom right negative -4.2 charge 'B'.

2. Relevant equations

E = F / q

F= Ke q1q2

--------

r^{2}

3. The attempt at a solution

I calculated the Force exerted on charge 'q' by 'A' and came up with 0.153 N and then used the cosine of 60 to obtain -0.77 as the x-component force and the sin of 60 to obtain -0.133 as the y-component force. Then I calculated the force exterted by 'B', the negative charge and obtained 0.107 in the 'i' direction giving me a sum force of 0.03 in the x direction. This SHOULD have given me part B, except two reasons why it was wrong. One, the units there say mN, but that did not work either, Two, I have done something conceptually wrong and cannot see it.

As for part A, I was going to use the above in E = F / q, but I first need the above part correct and even then I am not sure which charge is q.

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# Homework Help: Three-charge Electric Field Triangle.

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