Three masses in an elevator accelerating downwards

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SUMMARY

The discussion focuses on calculating the net force on the middle mass (m2=9.6 kg) in an elevator accelerating downwards at -2.5 m/s². The correct approach involves using the equation F=ma, resulting in a net force of 24 N acting upwards on the middle mass. The initial attempts to calculate the force neglected the spring's contribution, which was clarified later in the discussion. A diagram and free body diagrams (FBD) were suggested for better understanding.

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  • Understanding of Newton's Second Law (F=ma)
  • Knowledge of spring force calculations (Force(spring)=-kx)
  • Familiarity with free body diagrams (FBD) for visualizing forces
  • Basic concepts of mass and acceleration in physics
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  • Study the principles of free body diagrams (FBD) in physics
  • Learn about spring constants and their applications in mechanics
  • Explore the effects of acceleration on forces in non-inertial reference frames
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Korrie

Homework Statement


Three masses (m1=3.2, m2=9.6, and m3=6.4) hang from three identical springs in a elevator with a spring constant of 349N/m. The elevator is moving downwards at -3.7m/s and accelerating downwards at
a= -2.5m/s^2.

What is the magnitude of the net force on the middle mass?

Homework Equations


Force(spring)=-kx
F-mg= -ma
F= mg-ma

The Attempt at a Solution


I tried 9.6(9.81-2.5) and got 70.176 but that is wrong.
So I tried (9.6+6.4)X(9.81-2.5)= 116.96 but that is also wrong.

What am I doing wrong?
 
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Looks like you are neglecting the spring so far... What force does it exert, and how does that affect the acceleration?
 
berkeman said:
Looks like you are neglecting the spring so far... What force does it exert, and how does that affect the acceleration?
The force by the spring on the middle mass would the the sum of the bottom two masses time gravity.
The force by the spring would equal (9.6+6.4)(9.81)=156.96N

So to find the magnitude of the force on the middle mass I would take the 70.176N I gotten originally and add them?
 
Korrie said:
The force by the spring on the middle mass would the the sum of the bottom two masses time gravity.
The force by the spring would equal (9.6+6.4)(9.81)=156.96N

So to find the magnitude of the force on the middle mass I would take the 70.176N I gotten originally and add them?
Oh, I misunderstood the problem. You need to post a diagram of the setup please. Use the UPLOAD button in the lower right up upload a PDF or JPG of the setup. Thanks. Also, if you could show your FBD for each of the 3 masses on that diagram, it would be a help.
 
berkeman said:
Oh, I misunderstood the problem. You need to post a diagram of the setup please. Use the UPLOAD button in the lower right up upload a PDF or JPG of the setup. Thanks. Also, if you could show your FBD for each of the 3 masses on that diagram, it would be a help.
I'm unsure of my FBD for each of the masses but this is what I drew.
 

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Do we know the acceleration of the middle block?
Do we know the mass of the middle block?
What is the unknown that we want to calculate?
Is there an equation that relates those three quantities?
 
jbriggs444 said:
Do we know the acceleration of the middle block?
Do we know the mass of the middle block?
What is the unknown that we want to calculate?
Is there an equation tat relates those three quantities?
I tried the acceleration times the middle mass and that was wrong.
F=ma
(9.6kg)(-2.5m/s^2)= -24 N
 
Korrie said:
I tried the acceleration times the middle mass and that was wrong.
F=ma
(9.6kg)(-2.5m/s^2)= -24 N
That answer is correct.
 
jbriggs444 said:
That answer is correct.
Thank you, turns out the program wanted positive 24 N.
 
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