What Does Tie Pin 1 High to Enable the Output Mean in Electronics?

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"Tie pin 1 high to enable the output" means connecting the input pin to a high voltage level, typically the +5V supply, to activate the output of a component. This can be done directly with a trace or through a pull-up resistor, which is often recommended for testing purposes. It's essential to consult the component's datasheet for specific voltage and current specifications. The term "output enable" indicates that the pin must be high for the outputs to function correctly, commonly seen in tri-state buffers. Understanding this concept is crucial for effective PCB design and manufacturing.
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Enabling the output?
Hello,

I am new to engineering first year! I was wondering what "Tie pin 1 high to enable the output" My boss asked me to look at a crystal and asked me to do a small PCBA in PCB Express, but I am not sure what "high" is, is "high" tied to the +5V supply or is he asking for me to drop a pullup resistor? I would ask him again he is out on a honeymoon. Anything will help... Thanks!
 
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Welcome to PF. :smile:

Yes, "tie high" means to pull the input up to the supply rail. If the part is running off of 5V and GND, then pull that pin up to 5V. You can tie it directly to 5V with a trace, but a better practice is to pull it up through a medium-size resistor (10k-40k-ish). That allows testing of the enable/disable function in manufacturing, at the cost of one resistor. Your Manufacturing Engineering Department may have "Design for Manufacturability Rules" that will dictate whether you tie directly with a trace or through a resistor.

Always check the part's datasheet to be sure you understand the allowed supply voltages, input current specs, etc. Have fun learning!
 
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It means to connect that pin to the high supply, which it sounds like is +5V in your case. It probably doesn't matter whether you connect it to the high supply directly (with a wire), or whether you connect it through a resistor. Do you have the datasheet for the component you are working with? It might have some info. The chip is probably designed so that you have to connect this pin to the high supply in order for the outputs to drive out data, this is what "to enable the output" means. This is often called 'Output enable", and an output using this is called a "tri-state buffer". See this link for example:
https://www.electronics-tutorials.ws/logic/logic_9.html
 
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(Great minds think alike) :wink:
 
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Interesting! Makes sense. since this is my first board spin I am anxious to get his done! Thanks for your assistance!
 
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New Kid said:
"Tie pin 1 high to enable the output"
That statement refers an input logic signal that needs to be connected to a high = positive logical 1, to enable the outputs. That could be a positive supply, or it could be to some other logic signal that remains high = 1.
 
I am trying to understand how transferring electric from the powerplant to my house is more effective using high voltage. The suggested explanation that the current is equal to the power supply divided by the voltage, and hence higher voltage leads to lower current and as a result to a lower power loss on the conductives is very confusing me. I know that the current is determined by the voltage and the resistance, and not by a power capability - which defines a limit to the allowable...

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