Time constant for parallel RC circuit

Click For Summary
The time constant for a parallel RC circuit is determined by the formula τ = RC, where R is the total resistance in series with the capacitor. A participant initially suggested the time constant should be 1/2 RC due to a misunderstanding of the net resistance. Clarification was provided that the correct resistance affecting the time constant is the total resistance in series with the capacitor. The discussion also touched on the implications of using a non-ideal voltage source and how it could affect the circuit's behavior. Understanding the correct application of these principles is crucial for accurate calculations in circuit analysis.
Shivang kohlii
Messages
19
Reaction score
1

Homework Statement



Question 6.
IMG-20190103-WA0005.jpeg


Homework Equations


Time constant = RC

The Attempt at a Solution


I think answer should be 1/2 RC as Rnet = 1/2R and to convert it to single resistance form we should first find Rnet
But the answer is coming out to be RC . How?

<< Corrected Image added by Mentors >>

upload_2019-1-3_9-49-47.png
 

Attachments

  • IMG-20190103-WA0005.jpeg
    IMG-20190103-WA0005.jpeg
    18.1 KB · Views: 732
  • upload_2019-1-3_9-49-47.png
    upload_2019-1-3_9-49-47.png
    10.2 KB · Views: 504
Last edited by a moderator:
Physics news on Phys.org
Shivang kohlii said:
But the answer is coming out to be RC . How?
What is the total resistance in series with the Capacitor? That is the resistance that shows up in the time constant (assuming the voltage source is ideal)...

Are you familiar with Differential Equations? That would be one way to show how this works in this circuit...
 
Bonus Question -- What if the voltage source is not ideal? How would that change things? :smile:
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

Similar threads

  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
Replies
4
Views
3K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
19
Views
4K