Time Difference between two inertial frames of reference

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SUMMARY

The discussion centers on calculating the time difference between two inertial frames of reference, S and S', where S' moves at a velocity of 0.6c relative to S. The participant initially used the equation t = ϒ t' to find the proper time t' but arrived at an incorrect value of 1.6 × 10-7s instead of the correct 1.25 × 10-7s. The error was identified as a misunderstanding of the Lorentz Transformation, which accounts for both time and position in the calculation of time in different frames.

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Homework Statement


Let S and S' be two inertial frames of reference where S' is moving at a velocity of 0.6c relative to S.

When x = x' = 0, t = t' = 0, where t and t' are time of the clocks on S and S' respectively and x and x' are the x-coordinates of the S and S' frames respectively.

An event occurs at S when t = 2 × 10-7s and x = 50m. What is t' when the event occurs at S'?

Homework Equations


t = ϒ t'

The Attempt at a Solution


Let t' be the proper time.
t = ϒ t' where t = 2 × 10-7s and v = 0.6c.
Solving, I got t' = 1.6 × 10-7s but the answer is 1.25 × 10-7s.
What am I doing wrong?
 
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You've taken the wrong approach. The time an event takes place in S' depends on both the time and position it takes place in S.

Have you heard of the Lorentz Transformation?
 

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