Time Dilation due to Gravity: Formula Explained

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SUMMARY

The formula for time dilation due to gravity, particularly near a black hole, is expressed as the ratio T1/T2, where T1 is the time measured by an observer in a strong gravitational field and T2 is the time measured by an observer far away in an inertial reference frame. The specific formula is given by √(1 - r_s/r), where r is the Schwarzschild radial coordinate and r_s is the Schwarzschild radius of the black hole. This formula applies under the condition that both observers are static, with the distant observer ideally positioned at infinity. As the observer approaches the event horizon, the time dilation effect becomes significant, approaching zero.

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  • Understanding of general relativity concepts
  • Familiarity with Schwarzschild radius and coordinates
  • Knowledge of inertial and non-inertial reference frames
  • Basic grasp of gravitational effects on time measurement
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Dynamotime
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If possible can someone tell me what is the formula of time dilation for an object

Which theoretically is Not in orbit, Not moving but close in off to an black hole to be affect by the gravity of it.

It will be greatly appreciated.
 
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Time dilation in the context of gravity is usually used to refer to the ratio T1/T2 where
* T1 is the time between two spacetime events, E1 and E2, as measured by an observer O1 in a strong gravitational field; and
* T2 is the time between E1 and E2, as measured by an observer O2 that is far away and in an inertial reference frame.

A formula for this ratio, assuming the gravitational source is a spherically symmetric, non-rotating mass is

$$\sqrt{1-\frac{r_s}{r}}$$

where ##r## is the Swarzschild radial coordinate of O1 (which is analogous to the distance from the centre of the gravitational source) and ##r_s## is the Swarzschild radius of the source, which is the size to which the source would have to collapse to become a black hole. You can see from this formula that, as observer O1 approaches the event horizon of a black hole from the outside, the ratio heads towards 0.
 
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andrewkirk said:
Time dilation in the context of gravity is usually used to refer to the ratio T1/T2 where
* T1 is the time between two spacetime events, E1 and E2, as measured by an observer O1 in a strong gravitational field; and
* T2 is the time between E1 and E2, as measured by an observer O2 that is far away and in an inertial reference frame.

A formula for this ratio, assuming the gravitational source is a spherically symmetric, non-rotating mass is

$$\sqrt{1-\frac{r_s}{r}}$$

where ##r## is the Swarzschild radial coordinate of O1 (which is analogous to the distance from the centre of the gravitational source) and ##r_s## is the Swarzschild radius of the source, which is the size to which the source would have to collapse to become a black hole. You can see from this formula that, as observer O1 approaches the event horizon of a black hole from the outside, the ratio heads towards 0.
Actually, for this formula to be valid, both observers must be static - hovering via rockets or resting on a surface. Further, for that form to be valid, O2 must be hovering at 'infinity', stationary with respect to the spherically symmetric source. It is true that at infinity, stationary = inertial, but the characteristic that holds for the generalization where O2 is not at infinity is stationary rather than inertial. Stationary has proper acceleration and is not inertial except at infinity.
 
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Thank you so much for info
 
In an inertial frame of reference (IFR), there are two fixed points, A and B, which share an entangled state $$ \frac{1}{\sqrt{2}}(|0>_A|1>_B+|1>_A|0>_B) $$ At point A, a measurement is made. The state then collapses to $$ |a>_A|b>_B, \{a,b\}=\{0,1\} $$ We assume that A has the state ##|a>_A## and B has ##|b>_B## simultaneously, i.e., when their synchronized clocks both read time T However, in other inertial frames, due to the relativity of simultaneity, the moment when B has ##|b>_B##...

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