Time Dilation Explained: T=T(P)*γ Example

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SUMMARY

The time dilation equation, expressed as t = t(p) * γ, quantifies the difference in elapsed time between two observers in relative motion. In this discussion, clock A moves at 80% of the speed of light, resulting in a Lorentz factor (γ) of approximately 1.6667. After one hour measured by clock B, only 0.6 hours elapse on clock A. This example illustrates how to apply the time dilation equation to compare time measurements between stationary and moving clocks in different reference frames.

PREREQUISITES
  • Understanding of the Lorentz factor (γ) in special relativity
  • Familiarity with the concept of reference frames in physics
  • Basic knowledge of time measurement and synchronization of clocks
  • Awareness of the effects of relativistic speeds on time perception
NEXT STEPS
  • Study the derivation of the Lorentz transformation equations
  • Explore practical applications of time dilation in GPS technology
  • Learn about the implications of time dilation in high-speed particle physics
  • Investigate the effects of gravitational time dilation as described by general relativity
USEFUL FOR

Students of physics, educators teaching special relativity, and anyone interested in the implications of time dilation in modern technology and theoretical physics.

Dgonzo15
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Hello, can someone give me an explanation of the time dilation equation t=t(p)*γ? I know it's used to measure something about a difference in sense of time in different reference frames, but I don't know how to put it into context. Can someone give me an example where you would use the time dilation equation?
 
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Assume you have two clocks that are identical in construction.

Assume clock A is moving at 80% of the speed of light relative to clock B.

This would make γ equal to 1.6666...

t(p) would be the time that passes on clock A as measured by clock A

t is the time clock B measures for that time to pass on for clock A.

For example after 1 hr according to clock B, only 0.6 hrs will have passed on Clock B.

This assumes that the "observer" is at rest with respect to clock B.
 
Simple example, I am on the Earth with a clock that has been synchronized with another clock at some common origin (second clock on a plane moving past me at 50% speed of light). If I want to know what the clock reads on the plane in my reference frame, I have to use time dilation equation.
 

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