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Introductory Physics Homework Help
Calculating Speed for Time Dilation in the Twin Paradox
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[QUOTE="k3r0, post: 4489951, member: 486742"] My lecturer gave me the equation: [tex]\Delta T' = \gamma\Delta T[/tex] Wouldn't T' be for the astronaut and normal T is elapsed on Earth? Upon reflection I tried it the other way around and did this: [tex]\Delta T = \frac{2D}{c} = \frac{10c-yr}{c} = 10[/tex] [tex]\Delta T = \frac{\Delta T'}{\sqrt{1 - β^2}}[/tex] [tex]10=\frac{0.5}{\sqrt{1 - β^2}}[/tex] [tex]0.5 = 10\sqrt{1 - β^2}[/tex] [tex]β^2 = 0.9975[/tex] [tex]∴ β = 0.99875 (i.e. v = 0.99875c)[/tex] I think this seems to be a reasonable answer? Since you can never actually travel at the speed of light. I'm not convinced I've done it correctly though. [/QUOTE]
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Calculating Speed for Time Dilation in the Twin Paradox
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