Time Evolution operator in Interaction Picture (Harmonic Oscillator)

Click For Summary
SUMMARY

The discussion focuses on calculating the time evolution operator, ##\hat{U}_S(t,0)##, for a time-dependent harmonic oscillator using second-order perturbation theory. The Hamiltonian is defined as ##\hat{H}(t)=\hat{H}_0+\hat{V}(t)##, where ##\hat{H}_0=\hbar \omega \left( \hat{a}^{\dagger}\hat{a}+\frac{1}{2} \right)## and ##\hat{V}(t)=\lambda \left( e^{i\Omega t}\hat{a}^{\dagger}+e^{-i\Omega t}\hat{a} \right)##. The interaction picture transformation for the operator ##\hat{V}_I## is given by ##\hat{V}_I=e^{\frac{i}{\hbar}\hat{H}_0 t} \hat{V} e^{\frac{-i}{\hbar}\hat{H}_0 t}##. Participants emphasize the importance of correctly applying Equation 1 for the interaction picture to derive ##\hat{U}_S(t,0)##.

PREREQUISITES
  • Understanding of quantum mechanics, specifically the interaction picture.
  • Familiarity with perturbation theory in quantum systems.
  • Knowledge of harmonic oscillators and their Hamiltonians.
  • Proficiency in manipulating operators and kets in quantum mechanics.
NEXT STEPS
  • Study the derivation of the interaction picture and its applications in quantum mechanics.
  • Learn about second-order perturbation theory and its implications for time evolution operators.
  • Explore the mathematical techniques for integrating operator equations in quantum mechanics.
  • Investigate the role of ladder operators in quantum harmonic oscillators.
USEFUL FOR

Students and researchers in quantum mechanics, particularly those focusing on time-dependent systems, perturbation theory, and harmonic oscillators.

Xyius
Messages
501
Reaction score
4

Homework Statement


Consider a time-dependent harmonic oscillator with Hamiltonian

\hat{H}(t)=\hat{H}_0+\hat{V}(t)
\hat{H}_0=\hbar \omega \left( \hat{a}^{\dagger}\hat{a}+\frac{1}{2} \right)
\hat{V}(t)=\lambda \left( e^{i\Omega t}\hat{a}^{\dagger}+e^{-i\Omega t}\hat{a} \right)

(i) Compute ##\hat{U}_S(t,0)## using the interaction representation formula (Equation 1 in next section) to second order perturbation theory.
(ii) Compute ##\hat{U}_S(t,0)## using (Equation 2 in next section) to second order perturbation theory

Homework Equations



EQUATION 1:
U_I(t,0)=1-\frac{i}{\hbar}\int_0^t dt' V_I(t')+\left( \frac{-i}{\hbar} \right)^2 \int_0^t dt' \int_0^{t'} V_I(t')V_I(t'') + \dots

EQUATION 2:

U(t,0)=1+\sum_{n=1}^{∞}\left( \frac{-i}{\hbar} \right)^n\int_0^t dt_1 \int_0^{t_1} dt_2 \dots \int_0^{t_{n-1}}dt_n H(t_1)H(t_2)\dots H(t_n)



The Attempt at a Solution




So I know that for the interaction picture the transformation of the operator ##\hat{V}_I## is..

\hat{V}_I=e^{\frac{i}{\hbar}\hat{H}_0 t} \hat{V} e^{\frac{-i}{\hbar}\hat{H}_0 t}

I also know that both operators and kets evolve in time. So I use the interaction picture equation of motion on the ladder operators so I can obtain an expression for them as a function of time.

\frac{d\hat{a}}{dt}=\frac{1}{i\hbar}\left[ \hat{a},\hbar \omega \left( \hat{a}^{\dagger}\hat{a} + \frac{1}{2} \right) \right]

\frac{d\hat{a}^{\dagger}}{dt}=\frac{1}{i\hbar}\left[ \hat{a}^{\dagger},\hbar \omega \left( \hat{a}^{\dagger}\hat{a} + \frac{1}{2} \right) \right]

I then got..

\hat{a}(t)=\hat{a}(0)e^{-i\omega t}
\hat{a}^{\dagger}(t)=\hat{a}^{\dagger}(0)e^{i\omega t}

I plugged these into the expression for V to get..

\hat{V}=\lambda \left[ \hat{a}^{\dagger}(0)e^{i(\Omega + \omega)t} + \hat{a}(0)e^{-i(\Omega + \omega)t} \right]

So now what needs to be done, is to transform this into the interaction picture and then plug it into Equation 1 from above and integrate. But this seems very messy and I am having doubts if this is the correct way to go about this problem.

If anyone can shed some light onto this I would really appreciate it!
 
Physics news on Phys.org
I'm pretty sure your very last line is V_I; you don't need to transform it any more. Just plug it into Equation 1.
 

Similar threads

Replies
1
Views
2K
  • · Replies 0 ·
Replies
0
Views
2K
  • · Replies 10 ·
Replies
10
Views
3K
Replies
24
Views
3K
Replies
2
Views
4K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 1 ·
Replies
1
Views
3K
Replies
1
Views
2K
Replies
4
Views
3K