Time Invariance of System with x(t) and y(t) Equations

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SUMMARY

The discussion focuses on determining the time invariance of systems defined by the equations y(t) = ∫t+1t x(τ−α) dτ and y(t) = x(−t). The participant initially struggles with the implications of negative time and multiple terms within the x function. Ultimately, they clarify that the first equation involves a constant α, while the second equation's negative time does not affect the time invariance assessment. The conclusion reached is that the time invariance can be established by substituting x(t) with x(t−d) and checking if y(t) remains unchanged.

PREREQUISITES
  • Understanding of time invariance in systems theory
  • Familiarity with integral calculus and its applications in signal processing
  • Knowledge of the properties of functions, particularly with respect to time shifts
  • Basic understanding of the concept of negative time in signal processing
NEXT STEPS
  • Study the concept of time invariance in linear systems
  • Learn about the implications of negative time in signal processing
  • Explore the use of Laplace transforms in analyzing time-invariant systems
  • Investigate the effects of time delays on system outputs
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Students and professionals in electrical engineering, control systems, and signal processing who are analyzing system behaviors and properties related to time invariance.

Drew Carter
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Okay so the question looks like this
Determine whether the system with input x(t) and output y(t) defined by each of the following equations is time
invariant:
(c) y(t) =∫t+1t x(τ−α)dt where α is a constant;
(e) y(t) = x(−t);

There are more sub-questions but I was able to solve them. The reason I can't figure this out is the (d) has two items within the x function and the (e) question has a negative t within the x function. Help please. What do I do about the two items and negative t?
 
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What happens when you apply a time delay t -> t+d?
 
Simon Bridge said:
What happens when you apply a time delay t -> t+d?
The way I was thought is that for y1(t) your replace x(t) with x1(t), for y2(t) you replace x(t) with x2(t) which then equals x1(t-t0). Then if y2(t)= y1(t-t0). It's time invariant. My issue is doing that with two terms or a negative t
 
How is that an issue - did you do it and see what happens?
Note: both expressions only have "t" so where do you get "two terms" from?
 
Simon Bridge said:
How is that an issue - did you do it and see what happens?
Note: both expressions only have "t" so where do you get "two terms" from?
The first question has T and alpha, that's what I meant by two terms. It's fine, I figured it out
 
Most likely this can only be answered by an "old timer". I am making measurements on an uA709 op amp (metal can). I would like to calculate the frequency rolloff curves (I can measure them). I assume the compensation is via the miller effect. To do the calculations I would need to know the gain of the transistors and the effective resistance seen at the compensation terminals, not including the values I put there. Anyone know those values?

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