Time it takes an oscillating mass to reach a certain velocity

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Homework Help Overview

The problem involves determining the first time after t=0s at which the velocity of an object in simple harmonic motion reaches a specific value, given by the equation vx(t)= - (0.35 m/s)sin(20t + pi). Participants are exploring the implications of the sine function's periodicity in relation to the velocity equation.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss substituting the target velocity into the velocity equation and solving for time. There are questions about the periodic nature of the sine function and how it affects the solution. Some participants express confusion about the calculations and the implications of the results.

Discussion Status

The discussion is ongoing, with participants sharing their attempts and calculations. There is a recognition of the need to consider the periodicity of the sine function, and some guidance has been offered regarding the relationship between the period and the coefficient in the sine function. However, there is no explicit consensus on the correct approach or solution.

Contextual Notes

Participants are grappling with the implications of their calculations and the requirements of the online homework program, which may impose specific constraints on how answers are formatted or interpreted. There is mention of potential confusion regarding the use of radians in calculations.

Terp
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Hi everybody, this problem is giving me trouble and I was wondering if you could give me any advice.

Homework Statement



The velocity of an object in simple harmonic motion is given by vx(t)= - (0.35 m/s)sin(20t + pi), where t is in s.

What is the first time after t=0s at which the velocity is - 0.25 m/s?

Homework Equations



See the equation above.

The Attempt at a Solution



I simply plugged -.25 m/s in for vx(t) above and solved for t, so I got:

-0.25 = -0.35sin(20t + pi)
.714 = sin(20t + pi)

When I solve for t I get t = -.397e-1 = -.0397s, but mastering physics (the program I use to do homework online) say it's wrong. I entered the answer as positive. Anybody have any idea? Thanks a lot!

edit: I just went to see my professor and he helped me set it up, when finished we had sin(20t) = -5/7, but master physics says it's wrong.
 
Last edited:
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Trigonometric functions are periodic. This means that the function "repeats" itself over and over as you move along the X axis. If you visualize the sine involved in your problem, you'll realize that if you move sufficiently far to the right from -.0397 (and beyond 0), you'll get at a point p where vt(p) = vt(-.0397). That point is in fact -.0397 + Pi/10, because Pi/10 is the period of vt(x).
 
Thanks for the reply. Does that mean that the time it reaches -.25m/s is .275? (-0.397 + pi/10). Where did that 10 come from? Thanks!
 
The period of a sine function is given by 2pi/k, where k is the coefficient of x inside the bracket (i.e. for vt(x), the coefficient is 20). Really, it's not very useful for you to hear about this from me. You'd be better off learning better about trigonometric functions.
 
I believe that I do have a decent understand of trigonometric functions, I just can't figure out why this problem is giving me so much trouble. I can't be doing much wrong...]

I've got a graph of the wave drawn out and where the time will fall on the wave, but I just can't get it numerically.
 
Last edited:
But you just did; .275 s.
 
Thanks for the reply, but this darn program say it's wrong. I really don't like doing homework online.
 
Did you calculate arcsine in radians?
 
Yeah, arcsine(5/7) is .7956, then multiplying that my (1/20) as by my answer in the first post gives .0397
 
  • #10
Yeah, arcsine(5/7) is .7956, then multiplying that my (1/20) as by my answer in the first post gives .0397

You forgot to subtract pi before dividing by 20.

Calculating it myself, I get around -0.12 for t. -0.12 + pi/10 = 0.2, approximately.
 
  • #11
Thanks a lot for the help, Werg. Any more input from anybody would be appreciated!
 

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