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Homework Help: Time period formula-proof required

  1. Jan 30, 2010 #1

    IB1

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    Hello everyone, I'm new here, sorry if I make mistakes. My english is poor.

    Prove that :
    [tex] T=2\pi \sqrt{\frac{l}{g}} [/tex]
    where [tex]l[/tex] is length and [tex]g[/tex] is gravity

    I hope you understand my question, else: I will try to write it again.
    Thank you !
     
  2. jcsd
  3. Jan 30, 2010 #2

    tiny-tim

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    Welcome to PF!

    Hi IB1! Welcome to PF! :wink:

    Show us what you've tried, and where you're stuck, and then we'll know how to help! :smile:
     
  4. Jan 30, 2010 #3

    IB1

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    Thank you tiny-tim, It's nice joining this forum.

    As for the problem: Well, I don't know even how to start proving this. I was first thinking for any trigonometric solution but I can not understand how the period can be independent from the angle. Hope you understand to which angle I refer.

    It is not necessary to give an own proof, a link would be good enough.
     
    Last edited: Jan 30, 2010
  5. Jan 31, 2010 #4

    tiny-tim

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    Hi IB1! :smile:

    (just got up :zzz: …)

    It's difficult to know how to help without knowing how advanced your knowledge is …

    which part of the course is this in (for example, have you done calculus)?

    Maybe this will help … http://en.wikipedia.org/wiki/Pendulum" [Broken] :smile:
     
    Last edited by a moderator: May 4, 2017
  6. Jan 31, 2010 #5

    IB1

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    Thank you, the link was useful. You understood what I was asking :) . As for Calculus, yes -I know Calculus.

    It Seems that I was right, the period is not very independent from the angle [tex] \theta [/tex] .
     
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