Time Spent in Top and Bottom 25 cm of Basketball Player's Jump?

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SUMMARY

The discussion centers on calculating the time a basketball player spends in the top and bottom 25 cm of a 70 cm vertical jump. Using the constant acceleration formulae, the acceleration due to gravity is established as -9.81 m/s², and the velocity at the peak of the jump is 0 m/s. The time spent in the top 25 cm is approximately 0.14 seconds, while the time spent in the bottom 25 cm is about 0.14 seconds as well, indicating that the player spends equal time in both segments of the jump.

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A basketball player grabbing a rebound jumps 70 cm vertically.
How much (total) time does the player spend in the top 25 cm of this jump?
How much (total) time does the player spend in the bottom 25 cm of this jump?
 
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What are the relevant equations? What is your attempt at solving this?
 
WOW thanks for helping
 
You aren't going to be given an answer without showing that you've tried, and you definitely aren't going to be given an answer for being rude.

Have some hints:
a = -9.81 m/s/s
s (displacement) = 0.70 m
v at peak of jump = 0 m/s

use constant acceleration formulae.
 

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