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The attachment does not show work related to the question you posted, I guess you uploaded the wrong picture.James Ray said:
Thanks, I've changed the post.nrqed said:
I don't understand your calculation of the spring constant. 1.122 (2.4) must be > 2.James Ray said:
The equation for calculating the time taken for a mass on the end of a spring to hit a wall is t = 2π√(m/k), where t is the time, m is the mass of the object, and k is the spring constant.
The mass of the object has a direct impact on the time taken for it to hit the wall. The heavier the mass, the longer it will take for the object to reach the wall.
The spring constant is directly proportional to the time taken for the object to hit the wall. A higher spring constant will result in a shorter time for the object to reach the wall.
No, the amplitude of the oscillations does not affect the time taken for the object to hit the wall. The time taken is solely determined by the mass of the object and the spring constant.
The length of the spring has a direct effect on the time taken for the object to hit the wall. A longer spring will result in a longer time for the object to reach the wall, while a shorter spring will result in a shorter time.
