Time taken for two substances to reach equilibrium (equation?)

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The discussion centers on the time taken for two substances to reach thermal equilibrium, specifically in the context of an experiment involving beakers at different temperatures. The experiment demonstrated that a beaker at 25°C inside another at 100°C took 7 minutes to equilibrate. The participant questioned whether reducing the inner beaker's volume to 1/4 of the outer beaker would halve the time to reach equilibrium. Additionally, the time constant for a simple A <-> B chemical reaction is confirmed as 1/(k1 + k2), where k1 is the forward rate constant and k2 is the reverse rate constant.

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Da Apprentice
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I was wondering is there a formula that relates to the time it takes for a system to reach equilibrium? For example in an experiment I used one beaker at 25C inside another at 100C. The volume of the inner beakers was 1/2 that of the outer and with this combiation it took 7minutes for both beakers to reach the same temperature. If the volume of the inner beaker were changed to 1/4 of the outer beaker (starting at the same temperatures) would it take half the time to reach equilibrium as the previous example?
 
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This is more of a physics question. For a simple A <-> B chemical reaction with forward rate k1 and reverse rate constant k2 the time constant for reaching equlibrium is 1/(k1 + k2) if I remember correctly.
 
Nemus said:
This is more of a physics question. For a simple A <-> B chemical reaction with forward rate k1 and reverse rate constant k2 the time constant for reaching equlibrium is 1/(k1 + k2) if I remember correctly.

The time constant how is this then used? Forward and Reverse rate - are these the rates at which the equation takes to reach equilibrium? e.g. Graph attached?

EDIT: Ignore the writing at the bottom of the graph - I know it's a pointless statement
 

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