Time to Lift 50 15.0-kg Boxes at 41.4 W Output

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SUMMARY

The discussion focuses on calculating the minimum time required for a man to lift fifty 15.0-kg boxes to a height of 1.88 meters with an average power output of 41.4 watts. The relevant equations include the work-energy principle and the power formula, specifically P=W/Δt and P=Fv. The total energy required to lift the boxes is determined using gravitational potential energy, calculated as mgy. The solution involves determining the total work done and then using the power output to find the time.

PREREQUISITES
  • Understanding of gravitational potential energy (mgy)
  • Familiarity with power calculations (P=W/Δt)
  • Knowledge of basic physics equations related to work and energy
  • Ability to manipulate equations to solve for time
NEXT STEPS
  • Calculate the total energy required to lift the boxes using the formula mgy.
  • Determine the force exerted to lift one box and apply it in the power equation P=Fv.
  • Explore the relationship between power output and time in lifting scenarios.
  • Review examples of similar physics problems involving work and energy calculations.
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and energy, as well as educators looking for practical examples of power and work calculations.

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Homework Statement


If a man has an average useful power output of 41.4 W, what minimum time would it take him to lift fifty 15.0-kg boxes to a height of 1.88 m?


Homework Equations


1/2mv(final)^2 mgy(final) = 1/2mv(initial)^2 mgy(initial)

P=W/Δt

P=Fv

The Attempt at a Solution



Dont even know where to start
 
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How much energy is needed to lift those boxes?
 

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