Calculating Power: Torque on a 20 Kg Rod Pivoted at 6m | 500 Rad Rotation

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The discussion focuses on calculating the average and instantaneous power exerted by a motor on a 20 Kg slender rod, pivoted at its center with a length of 6 m, when subjected to a torque of 2400 Nm. To find the average power, the formula used is P_avg = Torque × Angular Velocity, where the angular velocity is derived from the total angle of rotation (500 rad). The instantaneous power can be calculated using P_inst = Torque × Angular Velocity at the specific angle of 500 rad.

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A 20 Kg slender rod pivoted at its center has a length of 6 m. A motor applied a torque of 2400 Nm on the rod to turn it from rest.
(a) Find the average power by the motor when the rod rotates an angle of 500 rad. _____________________
(b) Find the instantaneous power of the motor at the moment that the rod rotates an angle of 500 rad. ______________________

I am unsure how to start this.
 
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You should at least list some formulas you think you might need. For example, a formula for power at least.
 

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