- #1

starfish794

- 16

- 0

I used T=2pi*squareroot(x/9.8) and solved for x to be .357823847 as the length of the pendulum. Then I plugged that into delta L = (alpha)(Lo)(delta T) and found the change in L to be 0.000163168. I subtracted 0.000163168 from .357823847. Then I used T=2pi*squareroot(L/g) to find the period with the new length and got 1.199726369 so that the difference between the original period and the new period would be .000273631.

I don't understand why this is the wrong answer. Did I do it correctly and just make a math error?