Tiny question on differential (?) equations.

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SUMMARY

The discussion focuses on the potential function V(x) in an electric field, specifically its form derived from differential equations. At x=0, the first derivative dV/dx equals zero, indicating a minimum, while the second derivative d2V/dx2 is defined as kQ/(2 sqrt{2} L3). Consequently, the potential V(x) is expressed as V(x) = V(0) + @ x², where V(0) = (sqrt{2} kQ)/L and the constant @ is confirmed as kQ/(sqrt{2} L³). The inquiry also raises the question of whether @ should be kQ/(4 sqrt{2} L³) and discusses the even or odd nature of V(x).

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For the potential in an electric field is given:

http://img402.imageshack.us/img402/4162/naamloos8zn.gif

At x=0 V(x) is at a minimum so:

dV/dx =0 and d2V/dx2= kQ/(2 sqrt{2} L3)

Why does it follow that:

V(x) must be in the form V(x)= V(0) + @ x2 where V(0)= (sqrt{2} kQ)/L and the constant @ = kQ/ (sqrt{2} L 3) ?

Note that I haven't learned much yet on solving differential equations.
 
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Doesn't @ need to be kQ/ (4 sqrt {2} L 3)
 
Think about V(-x), i.e. is V(x) and odd or even function?
 

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