(adsbygoogle = window.adsbygoogle || []).push({}); The problem statement, all variables and given/known data

A cyclindrical pipe of length 29.5 cm closed at one end resonates with a tuning fork of frequency 864 Hz. Then mode of vibration of air in the pipe is(Velocity of sound in air=340m/s):

The attempt at a solution

V=Velocity, n=Frequency

If l_{1}is the first resonating length

then l_{1}= V/4n = 340/(4X864) = 0.0983m = 9.83 cm

Also, l_{2}is second resonating length

l_{2}= 3V/4n = 3 X 9.83 = 29.51 cm

This is the maximum resonating length possible in the pipe. Therefore the mode of vibration is 2.

But the answer given is 3! Please help...

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# Homework Help: To find out mode of vibration of air in a resonating pipe

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