To prove that a coherent state is an eigenstate of the annihilation operator

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SUMMARY

The coherent state defined as $$|\phi\rangle = \exp\left(\sum_{i}\phi_i \hat{a}^\dagger_i\right)|0\rangle$$ is indeed an eigenstate of the annihilation operator $$\hat{a}_i$$, satisfying the equation $$\hat{a}_i|\phi\rangle=\phi_i|\phi\rangle$$. To demonstrate this, one must apply the annihilation operator to the coherent state and utilize the properties of the exponential function, specifically expanding it in a Taylor series. This approach clarifies how the annihilation operator interacts with each term in the coherent state representation.

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chmodfree
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Moved from a technical forum, so homework template missing.
The definition of coherent state $$|\phi\rangle =exp(\sum_{i}\phi_i \hat{a}^\dagger_i)|0\rangle $$
How can I show that the state is eigenstate of annihilation operator a?
i.e.
$$\hat{a}_i|\phi\rangle=\phi_i|\phi\rangle$$
 
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chmodfree said:
How can I show that the state is eigenstate of annihilation operator a?

What does the annihilation operator do to each term in the sum?
 
PeterDonis said:
What does the annihilation operator do to each term in the sum?
Maybe one should add that the exponential function must be expanded in the Taylor series.
 

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