To prove that a field is complex

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The discussion centers on the properties of fields in mathematics, specifically addressing whether all non-ordered fields are complex. It is established that not all non-ordered fields are complex, as finite fields and fields of positive characteristic cannot be ordered. A field can be proven to be non-ordered if -1 cannot be expressed as a sum of squares. The discussion also clarifies that fields have specific axioms governing their operations, which cannot be arbitrarily defined.

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  • Understanding of field theory in mathematics
  • Familiarity with algebraic structures such as groups and rings
  • Knowledge of properties of complex numbers
  • Basic concepts of modular arithmetic
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  • Explore the characteristics of finite fields and their properties
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  • Investigate the relationship between sums of squares and field ordering
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I understand that the complex numbers form a "field" since the complex numbers are closed under addition, subtraction, multiplication, and division. And I understand the complex numbers are not an ordered field since it's not possible to define a relation z1<z2.

My question is: Are all not ordered fields necessarily complex? Then how would you prove that a field is not ordered, is that something that is observed in a system or imposed? Thanks.
 
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Take F={0,1} with

0+0=1+1=0,~1+0=0+1=1

and

0*0=1*0=0*1=0,~1*1=1

then F is a field that can not be ordered.
 
friend said:
I understand that the complex numbers form a "field" since the complex numbers are closed under addition, subtraction, multiplication, and division. And I understand the complex numbers are not an ordered field since it's not possible to define a relation z1<z2.

My question is: Are all not ordered fields necessarily complex?


No. Any finite field is not orderable (in fact, any field of positive characteristic is not ordered), or any non-real extension of \,\mathbb{Q}\, is not orderable...


Then how would you prove that a field is not ordered, is that something that is observed in a system or imposed? Thanks.


A field can be ordered iff -1 can't be expressed as a sum of squares, or equivalently iff a sum of squares equals zero iff every summand is zero.

DonAntonio
 
micromass said:
Take F={0,1} with

0+0=1+1=0,~1+0=0+1=1

and

0*0=1*0=0*1=0,~1*1=1

then F is a field that can not be ordered.

This seems like a very strange way to define + and *. Are you saying that in a field that we can define + and * and way we wish? Or is there some requirements for + and * so that they are consistent with each other?
 
friend said:
Are you saying that in a field that we can define + and * and way we wish?

A field is a specific algebraic structure with its own axioms so, no, we can't do anything we wish. What Micromass described is a special (very small) field.

http://en.wikipedia.org/wiki/Field_(mathematics )

I would suggest doing a little reading on Groups and Rings as well, to give Fields some context. Wikipedia might not be the best place for a beginner to start. Try a free textbook like this:

http://abstract.ups.edu/
 
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friend said:
This seems like a very strange way to define + and *.
It's not that strange at all. It's just like a clock with only two hours: 0 and 1. Take a look at this article: http://en.wikipedia.org/wiki/Modular_arithmetic

Are you saying that in a field that we can define + and * and way we wish? Or is there some requirements for + and * so that they are consistent with each other?

No, there are axioms that + and * must satisfy in order for (F, +, *) to be considered a field. Briefly, (F, +) must be an abelian group, ##(F^\times, *)## must be an abelian group and the distributive law must hold. You can read the axioms in more detail here: http://en.wikipedia.org/wiki/Field_(mathematics).
 

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