To what depth will the bullet penetrate the block in this case?

frosti
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Homework Statement


A 7.00 g bullet, when fired from a gun into a 1.00 kg block of wood held in a vise, penetrates the block to a depth of 7.60 cm. This block of wood is next placed on a frictionless horizontal surface, and a second 7.00 g bullet is fired from the gun into the block. To what depth will the bullet penetrate the block in this case?



Homework Equations


m1v1 + m2v2 = (m1+m2)vf


The Attempt at a Solution


I have no clue how to solve this problem. I don't really know what to do with the depth of penetration by the bullet. Can anyone please help?
 
on Phys.org


frosti said:

Homework Statement


A 7.00 g bullet, when fired from a gun into a 1.00 kg block of wood held in a vise, penetrates the block to a depth of 7.60 cm. This block of wood is next placed on a frictionless horizontal surface, and a second 7.00 g bullet is fired from the gun into the block. To what depth will the bullet penetrate the block in this case?



Homework Equations


m1v1 + m2v2 = (m1+m2)vf


The Attempt at a Solution


I have no clue how to solve this problem. I don't really know what to do with the depth of penetration by the bullet. Can anyone please help?
There's a significant loss of KE in part 1...like all of it, 1/2mv_b^2. In part 2 , apply conservation of momentum, and determine the total loss of KE. It' ll be a bit less; how does that ratio difference relate to the new depth of penetration?
 

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