1. The problem statement, all variables and given/known data A 7.00 g bullet, when fired from a gun into a 1.00 kg block of wood held in a vise, penetrates the block to a depth of 7.40 cm. This block of wood is next placed on a frictionless horizontal surface, and a second 7.00 g bullet is fired from the gun into the block. To what depth will the bullet penetrate the block in this case? 2. Relevant equations p= mv p1i + p2i = p1f + p2f and probably some other equations.. not really sure 3. The attempt at a solution ok well I would really appreciate it if someone could please kind of walk me through this problem, I'm not trying to get anyone to do my homework. In fact I already have the answer which is 7.35 cm but i really have no idea how to get it. I've read up on some previous posts about this question and I still just cant figure it out. I know it has something to do with conserving momentum and then turning that into conserving kinetic energy which will find the speed? Some thing like that, but could someone please kind of lay the format out, because i have a test tmw on this and I could really use some help. Thank you!