# Topology of de Sitter and black hole

1. Mar 18, 2006

### touqra

What does it mean in the statement "Topologically, de Sitter space is R × S^n-1..."
What is the topology of a Schwarzschild black hole?

2. Mar 18, 2006

### George Jones

Staff Emeritus
Every spacetime is a differentiable manifold, and every differentiable manifold is a topological space. The underlying topoogical space for de Sitter spacetime is the topological product R x S^3. Here, R is the set of real numbers, and is, roughly, a space of time coordinates. S^3, the compact 3-dimensional hypersurface of a 4-dimensional ball, is a space of spatial coordinates.

R^2 x S^S. Here, S^2 is the 2-dimesional surface of a 3-dimensional ball, and represents the spherical symmetry of Schwarzschild spacetime. R^2 is the set of ordered pairs of real numbers, and is the space of t and r coordinates.

Regards,
George