Topology - prove that X has a countable base

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Homework Help Overview

The discussion revolves around proving that a topological compact space \(X\) has a countable base, specifically focusing on the diagonal \(\Delta\) in the product space \(X \times X\) and its representation as an intersection of open sets.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore the idea of finding a candidate for a base and discuss the implications of compactness and Hausdorff properties. There are attempts to clarify the necessity of finite intersections of open sets and the relationship between these intersections and the proposed base.

Discussion Status

The conversation is ongoing, with participants raising questions about the reasoning behind taking finite intersections and the conditions needed for the collection of open sets to form a base. Some guidance has been provided regarding the need for modifications to the proposed base.

Contextual Notes

Participants express uncertainty about the definitions and implications of compactness and Hausdorff spaces, indicating a need for further clarification on these concepts as they relate to the problem at hand.

rustyrake
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Homework Statement



X - topological compact space

\Delta = \{(x, y) \in X \times X: x=y \} \subset X \times X

\Delta = \bigcap_{n=1}^{\infty} G_{n}, where G_{1}, G_{2}, ... \subset X \times X are open subsets.

Show that the topology of X has a countable base.

Homework Equations



The Attempt at a Solution



i have no idea what to start with. i don't really want to get a solution, just some clues...
 
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Let's first find a candidate of a base, shall we??

For each (x,x)\in G_n, we can find (x,x)\in U_x\times V_x\subseteq G_n. Now apply compactness on the U_x\times V_x.
 
meaning: choose a finite number of them?
and compactness of what?
 
rustyrake said:
meaning: choose a finite number of them?

Yes.

and compactness of what?

Of X.

You might also want to prove X to be Hausdorff...
 
hm, ok, and i do this for each n, and get countable family of finite families of small open sets, and my base are all those small open sets?

micromass said:
You might also want to prove X to be Hausdorff...
what do you mean?
 
rustyrake said:
hm, ok, and i do this for each n, and get countable family of finite families of small open sets, and my base are all those small open sets?

Not yet. You need to take all finite intersections as well.

Now try to prove that it is indeed a base. (you will need to make one last modification to the base in the end)

what do you mean?

Certainly you know what Hausdorff means?
 
micromass said:
Not yet. You need to take all finite intersections as well.

Now try to prove that it is indeed a base. (you will need to make one last modification to the base in the end)

:( i don't get it. why intersections? and... intersections of what?


Certainly you know what Hausdorff means?
yes, but according to the definition of compactness i know, X is Hausdorff and i don't have to prove it.
 
rustyrake said:
:( i don't get it. why intersections? and... intersections of what?

You found a collection of U\times V's. Now take all the finite intersections.

We will eventually want a base such that

\bigcap_{x\in G}{G}=\{x\}

yes, but according to the definition of compactness i know, X is Hausdorff and i don't have to prove it.

Ah, ok. Never mind then.
 
micromass said:
You found a collection of U\times V's. Now take all the finite intersections.

We will eventually want a base such that

\bigcap_{x\in G}{G}=\{x\}

still don't get it... maybe it's too late. i'll think more about it in the morning.

but: if i take only U's from those U\times V's... why isn't it already our base?
 

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