Torque and angular acceleration of a grindstone

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Homework Help Overview

The problem involves a grindstone, modeled as a solid disk, that is rotating and comes to rest due to an applied force. The context includes calculating the coefficient of friction based on the forces and torques acting on the grindstone.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Problem interpretation, Assumption checking

Approaches and Questions Raised

  • Participants discuss using energy principles and Newton's second law for rotation to analyze the problem. There are attempts to relate normal force to friction and torque, with questions about how to incorporate angular acceleration and the conversion of rotational speed units.

Discussion Status

The discussion is active, with participants exploring different approaches to relate the forces and torques involved. Some guidance has been provided regarding the relationship between normal force and friction, and the conversion of angular velocity units has been highlighted as a potential area of confusion.

Contextual Notes

Participants note the importance of unit conversion for angular velocity and question the validity of their calculations, particularly regarding the coefficient of friction exceeding expected limits.

BoldKnight399
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A grindstone in the shape of a solid disk with diameter 0.550 m and a mass of m = 50.0 kg is rotating at omega = 840 rev/min. You press an ax against the rim with a normal force of F = 160 N , and the grindstone comes to rest in 7.60 s. Find the coefficient of friction between the ax and the grindstone. You can ignore friction in the bearings.

To be honest, I want to draw a force diagram, but the thing is that the force then pushes into the grindstone. And then I was thinking about using Wtot-Wfriction=Change in Kinetic energy. But the thing is that I don't know how to use the Fnormal. If anyone can point me in the right direction, that would be great.
 
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BoldKnight399 said:
And then I was thinking about using Wtot-Wfriction=Change in Kinetic energy.
Better to use Newton's 2nd law for rotation.
But the thing is that I don't know how to use the Fnormal.
Hint: How does Fnormal relate to the friction force?
 
second law for rotations? torque=rXF? and Oh, fk=fnmewk. but I still don't know where to fit it into the equation/ or is that my F?
 
Yes, the friction force is the force that produces the torque.
 
so then torque=r X (fn*mewk)=I*alpha
but then how do I relate omega to alpha? is it alpha=domega/dt?
 
BoldKnight399 said:
so then torque=r X (fn*mewk)=I*alpha
Good.
but then how do I relate omega to alpha? is it alpha=domega/dt?
Yes. α = Δω/Δt. But convert ω to units of radians/second.
 
So i did that using my numbers and I get that the answer is 29.83 which makes absolutely no sense because mew cannot be bigger than 1. Did I do somethign wrong in the calculations: I got that my equations were:
r*Fnmewk=1/2mr^2*(w*2pi/t)
so
mewk=(1/2mr^2*(w*2pi/t))/(r*F)
so mew k=29 which is wrong
so did I just plug it into my calculator wrong or what?
 
BoldKnight399 said:
Did I do somethign wrong in the calculations: I got that my equations were:
r*Fnmewk=1/2mr^2*(w*2pi/t)
Note that you are given ω in units of rev/minute. How can you convert to radians/second?
 

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