Torque and segmented lever arms

  • Context: Undergrad 
  • Thread starter Thread starter vi1e
  • Start date Start date
  • Tags Tags
    Lever Torque
Click For Summary
SUMMARY

The calculation of torque with segmented lever arms requires understanding the concept of a "virtual" lever arm. When the weight is closer to the axis, the effective lever arm shortens, necessitating geometric analysis to determine its actual length. The torque is calculated as the weight (force) multiplied by the horizontal distance from the axis to the point directly beneath the weight. In this discussion, the resulting torque is approximately 9.5 lb-ft.

PREREQUISITES
  • Understanding of basic torque principles
  • Familiarity with lever arm geometry
  • Knowledge of force and weight measurements
  • Ability to visualize segmented lever systems
NEXT STEPS
  • Research the calculation of torque in segmented lever systems
  • Explore geometric methods for determining effective lever arm lengths
  • Learn about the implications of weight distribution on torque
  • Study real-world applications of torque in engineering and mechanics
USEFUL FOR

Engineers, physics students, and anyone interested in mechanical systems involving torque and lever arms will benefit from this discussion.

vi1e
Messages
1
Reaction score
0
My question is: How do you calculate torque when the lever arm is segmented? I have drawn a simple diagram to try to explain what I mean. Does the fact that the weight is now closer to the axis shorten my lever arm, or is the lever arm = D due to the fact that 10lbs is still being applied to the end of the first segment. Thanks.
 

Attachments

  • torque.jpg
    torque.jpg
    8.2 KB · Views: 717
Physics news on Phys.org
Assuming your segmented arms are rigidly attached - they don't rotate at the corner to the right - what you have is a new, shorter "virtual" lever arm, extending from the axis to the point where the weight is hung. You'd need to do the geometry to figure out its actual length, and what the vertical and horizontal components are. In this case, if the weight is hanging so it freely swings at the top, the resulting torque is the weight (force) times the horizontal distance from the axis to the point directly under the weight.

Scaling the drawing, I make it about 9.5 lb-ft.

Dave
 

Attachments

  • torque2.jpg
    torque2.jpg
    29.6 KB · Views: 653

Similar threads

  • · Replies 18 ·
Replies
18
Views
3K
  • · Replies 2 ·
Replies
2
Views
4K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 5 ·
Replies
5
Views
4K
  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 31 ·
2
Replies
31
Views
3K
  • · Replies 12 ·
Replies
12
Views
3K
  • · Replies 3 ·
Replies
3
Views
4K
  • · Replies 8 ·
Replies
8
Views
2K