So, i did a lab where we find the center of mass of a meter stick and then move the pivot point away from the CM and then add masses to bring it to equilibrium again. By finding the torque of the hanging mass, using the formula "Torque of hanging mass = Fh (Dist hanger to pivot)" we also find the torque of the center of mass since they are equal and opposite. We then use to formula "Fe(Dist from CM to pivot) = m(g)(dist from CM to pivot)" we can find the mass of the meterstick. One of the analysis questions is "how can the weight of the meterstick be cancelled out in future experiments?" Does anyone know the answer?