Torque Calculation for Sweeper machine Broom

[Tejas Patel]

Can anybody tell me how to calculate torque for rotating sweeper machine broom?

Broom Dia is - 0.6 m
Length - 2 m
Weight - 150 Kg
Rotating RPM - 150

 

[AdityaDev]

To start rotating any object, there has to be an unbalanced torque. Let the torque required be $\tau$.
What is the change in angular momentum when rod starts rotating with the required RPM starting from rest?

 

[Tejas Patel]

To start rotating any object, there has to be an unbalanced torque. Let the torque required be $\tau$.
What is the change in angular momentum when rod starts rotating with the required RPM starting from rest?

I don't know about angular momentum, But i know time. In 10 sec shaft pick its max speed 150 RPM.

 

[AdityaDev]

Are you familiar with this equation: $\tau=\Delta I\omega$

edit:$\tau = \Delta (I\omega)/\Delta t$

 

[Tejas Patel]

Are you familiar with this equation: $\tau=\Delta I\omega$

Yes in this i have calculated w, angular speed come is 15.7 rad/s. But i have confusion regarding I

 

[AdityaDev]

Assuming its a rod rotating about one end, I=(1/3)ML^2

 

[Tejas Patel]

Assuming its a rod rotating about one end, I=(1/3)ML^2

In this what is M and L?

 

[AdityaDev]

I is the moment of inertia which is analogous to mass in rotational mechanics. M is the mass and L is length of rod.

 

[Tejas Patel]

I is the moment of inertia which is analogous to mass in rotational mechanics. M is the mass and L is length of rod.

than I value is 2594.75 N-M2

 

[AdityaDev]

So you can find the torque using the equation in post 4

 

[Tejas Patel]

So you can find the torque using the equation in post 4

Than Unit come in N-m2/s ? bcz w unit is rad/s and I N-m2 so bit confuse in this

 

[AdityaDev]

Oops... I am very sorry.
its $\tau=I\alpha=I\frac{d\omega}{dt}$

 

[Tejas Patel]

Oops... I am very sorry.
its $\tau=I\alpha=I\frac{d\omega}{dt}$

Ok thank you so much.

 

[AdityaDev]

What I am trying to say is the change in angular momentum is $\Delta(I\omega)$.
Now you can find alpha is angular acceleration. Its is like acceleration.
$\alpha=\Delta\omega /\Delta t$

 

[Baluncore]

Can anybody tell me how to calculate torque for rotating sweeper machine broom?

I assume that you want to know the torque needed to keep it turning once it has reached speed and is being used. The operating torque will depend on the contact pattern with the swept area, the velocity of travel and the friction between the brush and the swept surface.

The size of the bristles on the brush will have a significant effect. Use the biggest bristles that will do the job.

Review the marketing information from manufacturers of sweeping machines. Make a list of published motor HP and brush RPM. From that you can calculate torque since power is torque multiplied by RPM.

 

[Tejas Patel]

I assume that you want to know the torque needed to keep it turning once it has reached speed and is being used. The operating torque will depend on the contact pattern with the swept area, the velocity of travel and the friction between the brush and the swept surface.

The size of the bristles on the brush will have a significant effect. Use the biggest bristles that will do the job.

Review the marketing information from manufacturers of sweeping machines. Make a list of published motor HP and brush RPM. From that you can calculate torque since power is torque multiplied by RPM.

Hello,

i am using it to clean solar panel, and my selected bristles dia is 0.3 mm also coefficient of sliding friction between solar panel and brush is 0.1 as per supplier data.
any specify calculation formula for same? Bcz i try as per post 12 but its value come too high.
please help me.

 

[Baluncore]

Broom Dia is - 0.6 m. Weight - 150 Kg.

A quick estimate begins with 150kg * 9.8 = 1470. N
Coefficient of friction is 0.1 so force needed is 1470 * 0.1 = 147N

Diameter is 600mm therefore radius is 300mm = 0.3m.
Torque needed is 147.N * 0.3m = 44.1 Newton.metre

 

[Tejas Patel]

Broom Dia is - 0.6 m. Weight - 150 Kg.

A quick estimate begins with 150kg * 9.8 = 1470. N
Coefficient of friction is 0.1 so force needed is 1470 * 0.1 = 147N

Diameter is 600mm therefore radius is 300mm = 0.3m.
Torque needed is 147.N * 0.3m = 44.1 Newton.metre

May be this start up torque, So can i need more torque to rotate it constant ?

 

[Baluncore]

May be this start up torque, So can i need more torque to rotate it constant ?

44.1 Nm is an estimate of the continuous operating torque while being used. You may need more torque to start the rotation, but that will only be if you need to accelerate it quickly, or if it is started while it is in contact with a panel.