- #1

slobberingant

- 11

- 3

- TL;DR Summary
- Need help understanding a vibrating force formula that was given to me at work.

I have been given a formula at work to use for calculating how much force is required to excite a vibrating machine with load. Only a proportion of material load on a vibrating machine is considered.

The formula is

F = 2*S / (K*M)

Where:

S = stroke (mm)

K = (140/w)^2

w = angular velocity (rad/s)

M = (M1 + (M1 + M2)) / (M1 * (M1 + M2)) (1/kg)

M1 = machine weight (kg)

M2 = material weight (kg)

I've manage to derive that the formula is based on Newton's second law and the acceleration of simple harmonic motion.

F = ma

a = Aw^2 - simple harmonic acceleration formula

Where:

A = amplitude (mm) => Stroke = 2*A

Therefore

F = mAw^2

My formula above is different in the following ways.

- w^2 ((rad/s)^2) becomes K - (140/w)^2 (1/((rad/s)^2)) but is divided rather than multiplied.

- m (kg) becomes M (1/kg) and is also divided rather than multiplied.

What does the M variable in my formula above do? - It seems like a ratio between machine and material mass. However, in isolation, the values it produces can be lower than the machine weight which would result in incorrect force values.

Where does the 140 constant in K come from?

The formula is

F = 2*S / (K*M)

Where:

S = stroke (mm)

K = (140/w)^2

w = angular velocity (rad/s)

M = (M1 + (M1 + M2)) / (M1 * (M1 + M2)) (1/kg)

M1 = machine weight (kg)

M2 = material weight (kg)

I've manage to derive that the formula is based on Newton's second law and the acceleration of simple harmonic motion.

F = ma

a = Aw^2 - simple harmonic acceleration formula

Where:

A = amplitude (mm) => Stroke = 2*A

Therefore

F = mAw^2

My formula above is different in the following ways.

- w^2 ((rad/s)^2) becomes K - (140/w)^2 (1/((rad/s)^2)) but is divided rather than multiplied.

- m (kg) becomes M (1/kg) and is also divided rather than multiplied.

What does the M variable in my formula above do? - It seems like a ratio between machine and material mass. However, in isolation, the values it produces can be lower than the machine weight which would result in incorrect force values.

Where does the 140 constant in K come from?