Torque, Equilibrium, and Center of Mass

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SUMMARY

The discussion focuses on a physics problem involving torque and equilibrium, specifically calculating how close a 70 kg painter can stand to the end of a 15 kg board without tipping it over. The equation used is τpainter = τboard, leading to the calculation (rpainter)(70 kg) = (1.5 m)(15 kg). The resulting distance calculated is 0.32 ft, but the correct answer is 1.2 m from the left end of the board, indicating a misunderstanding of the torque balance due to lack of visual support for the board's placement.

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This discussion is beneficial for physics students, educators teaching mechanics, and anyone interested in understanding the principles of torque and equilibrium in real-world applications.

Lyphta
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Homework Statement


While standing on a long board resting on a scaffold, a 70 kg painter paints the side of a house. If the mass of the board is 15 kg, how close to end can the painter stand without tipping the board over?
http://img146.imageshack.us/my.php?image=physicssl9.jpg


Homework Equations


\taupainter = \tauboard


The Attempt at a Solution


\taupainter = \tauboard
(rpainter) (70kg) = (1.5 m) (15kg)
70r = 22.5
r=.32 ft.

the answer was 1.2 m from left end of board.
 
Physics news on Phys.org
Sorry, without a picture showing how and where the board is supported, we cannot figure out the correct solution. We are certain, however, that ##\tau## is an incorrect answer.
 

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