Torque exerted on trap door by rope

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    Rope Torque
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SUMMARY

The discussion focuses on calculating the torque exerted on a trap door by a rope, specifically a trap door measuring 1.55 m in length and width, held at a 65.0° angle. The mass of the trap door is 14.6 kg. The torque can be calculated using the formula Torque = F(r), where F is the force exerted by the rope and r is the distance from the pivot point to the line of action of the force. The problem emphasizes the need to consider both the torque from the rope and the weight of the door, which must be resolved into components relative to the door's angle.

PREREQUISITES
  • Understanding of torque and its calculation using Torque = F(r)
  • Knowledge of statics and equilibrium conditions in mechanics
  • Ability to resolve forces into components, particularly weight
  • Familiarity with the concept of center of mass
NEXT STEPS
  • Study the principles of static equilibrium in mechanics
  • Learn how to resolve forces into normal and parallel components
  • Explore the concept of torque and its applications in engineering
  • Investigate the calculation of moments about a pivot point
USEFUL FOR

Students in physics or engineering courses, particularly those studying statics, mechanics, or torque calculations. This discussion is beneficial for anyone needing to understand the forces acting on a trap door system.

streeter
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Homework Statement


A trap door, of length and width 1.55 m, is held open at an angle of 65.0° with respect to the floor. A rope is attached to the raised edge of the door and fastened to the wall behind the door in such a position that the rope pulls perpendicularly to the trap door. If the mass of the trap door is 14.6 kg, what is the torque exerted on the trap door by the rope?



Homework Equations


Torque=F(r)


The Attempt at a Solution



Honestly I have no clue.
 
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This is a statics problem, so the sum of the moments/torques must equal zero. Find each of the moments about the pivot. One of the moments (torques) is due to the rope which is acting perpendicular to the plane (and moment arm) of the trapdoor. The other is the weight, which must be resolved into normal and parallel components with respect to the plane of the trapdoor.

Think about center of mass.
 

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