Torque,flywheels and angular acceleration

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SUMMARY

The discussion focuses on calculating angular acceleration using Newton's second law for rotation, expressed as Torque = Iα, where I represents the rotational inertia. A user reports achieving an angular acceleration of 1000 rad/s² for a 10 kg disc with a radius of 0.1 m under a torque of 50 Nm. This value is questioned as potentially excessive, indicating a need for verification of the calculations and assumptions regarding inertia.

PREREQUISITES
  • Understanding of Newton's second law of motion applied to rotation
  • Knowledge of rotational inertia (I) and its calculation
  • Familiarity with torque and its units (Nm)
  • Basic principles of angular acceleration (α)
NEXT STEPS
  • Review the calculation of rotational inertia for different shapes, particularly discs
  • Learn about the relationship between torque, angular acceleration, and inertia in rotational dynamics
  • Explore the effects of varying torque on angular acceleration in practical scenarios
  • Investigate common misconceptions in angular motion calculations
USEFUL FOR

Physics students, mechanical engineers, and anyone involved in rotational dynamics or torque applications will benefit from this discussion.

tomhitchmough
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ive been trying to do this question all summer to no joy. I've got a flywheel in motion which then has a torque applied for short period and i need to find the angular acceleration. i know its something to do with inertia but I am completely lost cheers
 
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Newton's 2nd law applied to rotation will give you the angular acceleration: Torque = Iα. (I is the rotational inertia of the flywheel.)
 
yer cheers I've done that and I've got a angular acceleration of 1000 rads-2 for 10kg disc radius 0.1m for a torque applied of 50Nm which seems a bit big
 

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