- #1
wallace13
- 31
- 0
A woman who weighs 496 N is leaning against a smooth vertical wall. Find
Fx= 0= -F Wall = Gx
Fy= 0= Gy- Fgwoman
(a) the force FN (directed perpendicular to the wall) exerted on her shoulder by the wall
T= 0= -Fgw*sin30* ((1.1+.4)/2)- Fgw sin 30 (1.1) + F wall cos 30 (1.5)
F wall= 353.1844
(b) horizontal and
(c) vertical components of the force exerted on her shoes by the ground.
I understand that the force of the horizontal is equal to the force of the wall, and the force of the vertical components is equal to the woman's weight, but I am not sure what is wrong with my equation, because F wall is incorrect.