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A woman who weighs 496 N is leaning against a smooth vertical wall. Find

Fx= 0= -F Wall = Gx

Fy= 0= Gy- Fgwoman

(a) the force FN (directed perpendicular to the wall) exerted on her shoulder by the wall

T= 0= -Fgw*sin30* ((1.1+.4)/2)- Fgw sin 30 (1.1) + F wall cos 30 (1.5)

F wall= 353.1844

(b) horizontal and

(c) vertical components of the force exerted on her shoes by the ground.

I understand that the force of the horizontal is equal to the force of the wall, and the force of the vertical components is equal to the woman's weight, but I am not sure what is wrong with my equation, because F wall is incorrect.

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# Homework Help: Torque of a woman leaning against a wall

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