Torque of suspended meter stick

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SUMMARY

The discussion centers on calculating the tension in the string attached to a 1.0-N uniform meter stick suspended horizontally with additional weights. The weights of 2.0 N at the 10 cm and 50 cm positions, and 3.0 N at the 60 cm position, create a torque that must be balanced by the tension in the string at the 100 cm end. The correct tension is determined to be 3.5 N, as calculated using the sum of torques and forces, highlighting the importance of accounting for the stick's mass in torque calculations.

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  • Understanding of torque and its calculation
  • Familiarity with the principles of static equilibrium
  • Knowledge of force summation in physics
  • Basic concepts of weight and mass
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This discussion is beneficial for physics students, educators, and anyone interested in understanding the mechanics of forces and torques in static systems.

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Homework Statement


A uniform 1.0-N meter stick is suspended horizontally by vertical strings attached at each end. A2.0-N weight is suspended from the 10-cm position on the stick, another 2.0-N weight is suspendedfrom the 50 cm position, and a 3.0-N weight is suspended from the 60 cm position. What is the tension in the string attached at the 100-cm end of the stick?
a. 1.9 N
b. 3.0 N
c. 3.5 N
d. 4.0 N
e. 4.4 N



Homework Equations



sum of torques and sum of forces

The Attempt at a Solution



2*.1+2*.5+3*.6=F(1)

i get the tension to be 3 but the correct one should be 3.5, i don't see where i lose the .5 Newtons
 
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Does the meter stick have mass? Where does the torque for the stick's mass act?
 

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