Torque on a rectangular loop with attached mass
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The magnitude of the force on each wire is F1 = I*B*L down (theeta is 90) and
F2 = mg - I*B*L down
A. Resulting torque = I*B*L*(w/2) - (mg - I*B*L)(w/2) = I*B*L*w - mg(w/2) = 0 (for balance)
B. Resulting torque = (I*A)*B - mg(w/2) = I*L*w*B - mg(w/2) = 0
gives the current I = mg/2BL
F2 = mg - I*B*L down
A. Resulting torque = I*B*L*(w/2) - (mg - I*B*L)(w/2) = I*B*L*w - mg(w/2) = 0 (for balance)
B. Resulting torque = (I*A)*B - mg(w/2) = I*L*w*B - mg(w/2) = 0
gives the current I = mg/2BL
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